Solution :
= / n = 25 / 100 = 2.5
= P[(265 - 265) / 2.5 < ( - ) / < (267 - 265) / 2.5)]
= P(0 < Z < 0.8)
= P(Z < 0.8) - P(Z < 0)
= 0.7881 - 0.5
= 0.2881
Furnace repair bills are normally distributed with a mean of 265 dollars and a standard deviation...
Furnace repair bills are normally distributed with a mean of 265 dollars and a standard deviation of 25 dollars. If 100 of these repair bills are randomly selected, find the probability that they have a mean cost between 265 dollars and 267 dollars. O 0.2119 O 0.2881 O 0.7881 O 0.5517
13) Furnace repair bills are normally distributed with a mean of 265 dollars and a standard deviation of 20 dollars. If 64 of these repair bills are randomly selected, find the probability that they have a mean cost between 265 dollars and 267 dollars. A) 0.2119 B) 0.7881 C) 0.2881 D) 0.5517
Furnace repair bills are normally distributed with a mean of 267 dollars and a standard deviation of 20 dollars. If 64 of these repair bills are randomly selected, find the probability that they have a mean cost between 267 dollars and 269 dollars. 0.5517 0.2119 0.2881 0.7881
QUESTION 12 Provide an appropriate response. Furnace repair bills are normally distributed with a mean of 271 dollars and a standard deviation of 25 dollars. If 100 of these repair bills are randomly selected, find the probability that they have a mean cost between 271 dollars and 273 dollars. 0.2881 0.7881 0.5517 @ 0.2119
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