Pb(NO3)2 here is Strong electrolyte
It will dissociate completely to give [Pb2+] = 0.21 M
At equilibrium:
PbI2 <----> Pb2+ + 2 I-
0.21 +s 2s
Ksp = [Pb2+][I-]^2
1.4*10^-8=(0.21 + s)*(2s)^2
Since Ksp is small, s can be ignored as compared to 0.21
Above expression thus becomes:
1.4*10^-8=(0.21)*(2s)^2
1.4*10^-8= 0.21 * 4(s)^2
s = 1.291*10^-4 M
Answer: 1.3*10^-4 mol/L
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