NaI here is Strong electrolyte
It will dissociate completely to give [I-] = 0.023 M
At equilibrium:
PbI2 <----> Pb2+ + 2 I-
s 2.3*10^-2 + 2s
Ksp = [Pb2+][I-]^2
1.4*10^-8=(s)*(2.3*10^-2+ 2s)^2
Since Ksp is small, s can be ignored as compared to 2.3*10^-2
Above expression thus becomes:
1.4*10^-8=(s)*(2.3*10^-2)^2
1.4*10^-8= (s) * 5.29*10^-4
s = 2.647*10^-5 M
Answer: 2.6*10^-5 M
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