Question

3 What spin only magnetic moment (uso) expected for each of the following complexes. (a) [MnBra] (d) [FeC16] 19 NICOW" (c) [V(H2O)]2+ (b) [Ni(H2O)]2+ (e) [CoBraj? TAROT (1) Mo(CO)6

Answer 1

Spin Magnetic Moment u = ln(n+8) 11 where n = no of cupaired tlich bus a) (Mn Bry] . Mn -4=-1 - Mn =+3. Mn = [Ar] 45 ² 3ds Most = [Ar] usº 3d" . 4 unpaired election .: M = J4 (4+2) = J 24 = 4.90 BM 17 TINO ( od 12+ - di Ni 2+ = Nit660) = + 9. Ni z t&. [Au] 45² 308 Cal 45° 3d8 Wludos

of unpaired election = 2 :: H = 12(7+2) = 2.84 BM [VCH.06227 V + 6(0) = 2 V = g. V =[Ar] 4523d3 u2+ = [Ar] 45 3d Ulpaired election = 3 ve M = J3(3+2) i 3.87 BM.. fe - 6 = -3 . fe + 3 Fe=TAL] 45² 3d Fe 3+ = Cal] 45° 3ds unpalied election = 5 M = J5 (5+2) = √35 = 5.98 BM

e) { Co Ber 4] Co -4 = -2 Co= +2 Co = [Ar] 4s 3d - Cozt- [A2J45°3/? No of unputed election M = √3(3+9) =VIS ma000 3 = 3-87BM Mollo - Mot 660)zo Mozo Mo = [kr] 4 d 55 No of unpaired election = 6 M = 16(6+2) = 6.93 B.M