Question

) bet 5.00) and a 3.40-29 object Consider the following distribution of objects: a 4,00 kg object with its center of gravity at (0 of mass 7.00 kg be placed so that the center of gravity of the four-object arrangement (100,0) - Where should a fourth object Need Help? Read More

Answer 1

Let us consider the coordinate of fourth object (7.00 Kg) is (x,y). The center of mass coordinate of the four body system is (0,0). Therefore, the x-coordinate for center of mass will be

$0=\frac{\sum m_{i}x_{i}}{\sum m_{i}}=\frac{3.40\times 1.00+7.00\times x}{4.00+2.20+3.40+7.00}=\frac{3.40+7.00x}{16.6}$

$\therefore x=-0.49\ m$

Similarly y-coordinate will be

$0=\frac{\sum m_{i}y_{i}}{\sum m_{i}}=\frac{2.20\times 5.00+7.00\times y}{4.00+2.20+3.40+7.00}=\frac{11.00+7.00x}{16.6}$

$\therefore y=-1.57\ m$

Therefore, the mass 7.00 Kg should be placed at (-0.49, -1.57) m.