Question

This assignment is due at the beginning of your lab period in the next week Name: pts: 115 pts Consider the following reaction between cyclohexene and diatomic bromine. .. oke 40 ml 35 ml Cyclohexene (C6H12): molecular weight = 82.14 g/mol; density = 0.811 g/ml Bromine (Bra): molecular weight = 159.81 g/mol; density = 3.12 g/mL (1 point each) 1. How many grams of cyclohexene are involved in this reaction? 2. How many grams of bromine are involved in this reaction? 3. How many moles of cyclohexene are involved? How many moles of bromine are involved? Which compound is the limiting reagent? What is the maximum number of moles of product that can form? What is the maximum number of grams of products that can form? What would be the percent yield if 57 grams of product are isolated?

Answer 1

1. Mass = Volume X Density = 40 ml x 0.8 11 g/mL = 32.44g . (Cyclohexene) 1.2. Mass of Promine = 35 mL X 3.12 g / m/ = 109. Lg 3. No of moles of cyclohexene Mass = 32.448 = 0.3950ml Molar mass 82.14 g/mol - 4. No of moles of Bromine = 109.2g = 0.6833 male 159.81g/mol - 5. 1 male cyclohexene reacts with 1 mole Bromine. As -- no. of moles of cyclohexene are less so, Cyclohexene -- limiting Reagent b. No of moles of product formed= No of moles of - Cyclohexene reacted = 0.3950 mali I 7 Mass of product that can be formed = No of mlyx Molar mass (Theoretical Yield) = 0.3450 ml x 241.95glind... = 95.51g . 8. % Lield = Obtained Yield x 100% Theoretical Yield 57 g x 100% = 59.64% 95.579 Ž 60%