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26. In a competitive inhibitor experiment, measured KM without inhibitor is 75 nM. After additing 3...
6X 10+ 200 3. What concentration of competitive inhibitor is required to yield 75% inhibition at...
6X 10+ 200 3. What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration of 1.5 X 10M if Km-2.9 X 10+M and Ki-2. X 10M? The followina cat we winiaran Medan Termine whether
a) What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration...
a) What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration of 1.5x10-3 M if Km=2.9x10-4 and Ki=2x10-5? b)To what concentration must the substrate be increased to re-establish the velocity at the original uninhibited value?
21. When you measure an enzyme reaction both without and with several concentrations of an inhibitor,...
21. When you measure an enzyme reaction both without and with several concentrations of an inhibitor, the calculated Vmay for all of the reactions remains constant. However, KM is changing with addition of the inhibitor to apparent higher values (Km apparent). What kind of inhibition is this likely to be? a. Competitive inhibition. b. Uncompetitive inhibition. c. Mixed inhibition. d. Pure noncompetitive inhibition.
a. what are the values of Vmax and Km in the abscence if the inhibitor what...
a. what are the values of Vmax and Km in the abscence if the
inhibitor what are the values of Vmax and Km in the presence of the
inhibitor?
b. what type of inhibition is it?
c. what is the dissociation constant (Ki) of the
inhibition?
***d. graph a linear scatter plot including equation.
Homework (CHE 407) The initial velocity for an enzyme-catalyzed reaction is measured at various initial substrate concentration [S]o, in the absence and in the presence of...
An enzyme binds to a competitive inhibitor with Kd = 1.2 × 10-6 M at pH 7.0 and 25°C.
An enzyme binds to a competitive inhibitor with Kd = 1.2 × 10-6 M at pH 7.0 and 25°C.(a)At what inhibitor concentration will 75% of the enzyme be bound to the inhibitor if there is no substrate present? (b) This enzyme has a Km of 4.0 × 10-5 M and a Vmax of 50 μM/s. At a substrate concentration of 3.0 × 10-4 M, calculate (i) the velocity of reaction in the presence of the inhibitor at 4.8 x 10-5 M (ii) the degree of...
A different experiment yields the following kinetic data Substrate] (mM)Vo (uM/min) no inhibitorVo (uM/min)+7 nM inhibitor...
A different experiment yields the following kinetic data Substrate] (mM)Vo (uM/min) no inhibitorVo (uM/min)+7 nM inhibitor 0.02 0.04 0.10 0.25 1.00 2.50 0.8 2.9 8.6 24 36 50 Plot the data for the kinetics of the enzyme (with and without the inhibitor) in a double reciprocal (Lineweaver-Burk) plot. Keep in mind that the x axis is 1/[S] and the y axis is 1/Vo. If you are using Excel you want to choose the (x,y) scatter plot (without a ne). You...
CHEM3250 Assignment-Enzyme Inhibition Consider the data below for an enzyme catalyzed reaction. T...
CHEM3250 Assignment-Enzyme Inhibition Consider the data below for an enzyme catalyzed reaction. The rate of the reaction has been determined with and without an inhibitor. A total concentration of enzyme of 20 uM was used in the experiment. SHOW WORK AND UNITS!!! Without Inhibitor With Inhibitor [substrate] (mM)Rate of formation of te of formation of product product (mM/min) mM/min) 6.67 5.25 0.49 7.04 38.91 1.0 2.2 6.9 41.8 44.0 1.5 3.5 1 a) On the same graph, plot the data...
. ous enzyme 'happyase catalyzes t the conversion of SAD to HAPPY with a Keat 100...
. ous enzyme 'happyase catalyzes t the conversion of SAD to HAPPY with a Keat 100 sec 40 35 30 25 20 10 10 20 30 40 50 60 70 90 100 110 ISADI QIM A kinetic experiment was conducted and the intitial velocity of the reaction as a function of SAD concentration is shown above. The initial velocity at 1 mM [SAD] was measured to be 40 nM/sec. a) What is the total [happyase] used above (make sure to...
3. Below is a Lineweaver-Burke plot of an enzyme reaction in the presence and absence of...
3. Below is a Lineweaver-Burke plot of an enzyme reaction in the presence and absence of an inhibitor. 2.4 2.3 2.2 2.1 2 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1 0.9 0.8 < 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 -0.1 -0.2 -0.3 -0.4 -0.5 -0.6 -0.7 -0.8 . . . . . -1 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 O 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1/[S]...
ignore work i know its not correct 5. A 75 kg person is traveling at a velocity of 3.0 miles/h. What is the uncer...
ignore work i know its not correct
5. A 75 kg person is traveling at a velocity of 3.0 miles/h. What is the uncertainty in the person's velocity if their position is measured with a precision of 1.0 nm? (3 points) V 3.6 mln precson of 1 onm A. 5.3 x 1026 m/s B. 8.8 x 10-27 m/s C. 7.0 x 10-28 m/s p(9.1 013.6 D. 5.2 x 10-37 m/s 07 6K10-24 E. 8.8 x 10-37 m/s 2783X1084 z.7 33x1033...
6X 10+ 200 3. What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration of 1.5 X 10M if Km-2.9 X 10+M and Ki-2. X 10M? The followina cat we winiaran Medan Termine whether
21. When you measure an enzyme reaction both without and with several concentrations of an inhibitor, the calculated Vmay for all of the reactions remains constant. However, KM is changing with addition of the inhibitor to apparent higher values (Km apparent). What kind of inhibition is this likely to be? a. Competitive inhibition. b. Uncompetitive inhibition. c. Mixed inhibition. d. Pure noncompetitive inhibition.
a. what are the values of Vmax and Km in the abscence if the
inhibitor what are the values of Vmax and Km in the presence of the
inhibitor?
b. what type of inhibition is it?
c. what is the dissociation constant (Ki) of the
inhibition?
***d. graph a linear scatter plot including equation.
Homework (CHE 407) The initial velocity for an enzyme-catalyzed reaction is measured at various initial substrate concentration [S]o, in the absence and in the presence of...
A different experiment yields the following kinetic data Substrate] (mM)Vo (uM/min) no inhibitorVo (uM/min)+7 nM inhibitor 0.02 0.04 0.10 0.25 1.00 2.50 0.8 2.9 8.6 24 36 50 Plot the data for the kinetics of the enzyme (with and without the inhibitor) in a double reciprocal (Lineweaver-Burk) plot. Keep in mind that the x axis is 1/[S] and the y axis is 1/Vo. If you are using Excel you want to choose the (x,y) scatter plot (without a ne). You...
CHEM3250 Assignment-Enzyme Inhibition Consider the data below for an enzyme catalyzed reaction. The rate of the reaction has been determined with and without an inhibitor. A total concentration of enzyme of 20 uM was used in the experiment. SHOW WORK AND UNITS!!! Without Inhibitor With Inhibitor [substrate] (mM)Rate of formation of te of formation of product product (mM/min) mM/min) 6.67 5.25 0.49 7.04 38.91 1.0 2.2 6.9 41.8 44.0 1.5 3.5 1 a) On the same graph, plot the data...
. ous enzyme 'happyase catalyzes t the conversion of SAD to HAPPY with a Keat 100 sec 40 35 30 25 20 10 10 20 30 40 50 60 70 90 100 110 ISADI QIM A kinetic experiment was conducted and the intitial velocity of the reaction as a function of SAD concentration is shown above. The initial velocity at 1 mM [SAD] was measured to be 40 nM/sec. a) What is the total [happyase] used above (make sure to...
3. Below is a Lineweaver-Burke plot of an enzyme reaction in the presence and absence of an inhibitor. 2.4 2.3 2.2 2.1 2 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1 0.9 0.8 < 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 -0.1 -0.2 -0.3 -0.4 -0.5 -0.6 -0.7 -0.8 . . . . . -1 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 O 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1/[S]...
ignore work i know its not correct
5. A 75 kg person is traveling at a velocity of 3.0 miles/h. What is the uncertainty in the person's velocity if their position is measured with a precision of 1.0 nm? (3 points) V 3.6 mln precson of 1 onm A. 5.3 x 1026 m/s B. 8.8 x 10-27 m/s C. 7.0 x 10-28 m/s p(9.1 013.6 D. 5.2 x 10-37 m/s 07 6K10-24 E. 8.8 x 10-37 m/s 2783X1084 z.7 33x1033...
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