Question

PLL35 W 13. For the following redox reaction, 2CBn 2CsBr a) write the two half reactions b) identify what is oxidized and what is reduced c) identify the oxidizing agent and the reducing reagent 20s + Br2 -> 2 Cs Br 20s → 205* Poxidized) 2e + Brz- Br" creduced). Reducing feagent: oxidizing agent. 14. Write the Molecular. Ionic and Net Ionic equations for the reaction between Mg(NO3)2 (aq) and LisPO4 (aq). Mg(NO3)2 + Liz PO4 - MADO4 + Liz (NO) Mgth (NOJ- + L + PO ² - Mg Pou 3 Mg 2 + 2 P04 ² -> Mg: PO4)2 thin tint 15. Calculate the volume in mL required to provide 4.37 g of lithium chloride from a 0.135 M solution. IL 4.379x Imol x 1000 mL

Answer 1

(-) (-1) 132 CA + B ------, 2 CAN" Half reaction - Change in orication stule ü eso der are lost) >20s +2e". Om'olati con Haly routin : 26 - Reduction Holf reaction t o (02 (0) Bro +2e (0) - 2 Br change in onidation state is a so 2 e are gained. (b) Cs i getting onidined (from Ca - Cat) Bry is getting and reduced (from By Bril). 10 Onidining agent is the agent which midises the substance a Uself gets reduced theus Bry acts as an onidining agent. Reduring agent is the agent which reduces the substance a itself gets onidised le Cs is the reducings agent 1w{Mylenos), (aq) + KembangaLy Poy cap) > My Por] cas #bling, (ap) . folecular equation,

Ionic equation : 3 Mg2+ +6NO lagi lags + Bli" +2 PO," (aq) la ~Mg, (PO4)«) +6litas) tvO precipitate Net Jane equation; 3Mg ² + + 690 +64 + 2por 1. Tag l ay Car - My (pouzes) + Shot + 50g (aq) . laqlar 7 Mg 2+ (29) + 2 pour lag) - My (104), (1) or (d) (precipitate) 15. . given mass of lithium Chloride (lice) = 4.379 Moler mass of Lice = 7+35.5 = 42.5g/mote .. . no. of moles of lice a given mass of like = 4,37 Molermass of lice 42.5 mole Molarity is defined as the no. of moles of solute (lices dissolved in le of solution Mc 726 LXlvo veme) V5 4737 X1000 . 42,5 80,135 lu-761.65 me.