Homework Answers
Concept: - properties of electric field and condition of minimum of a function is used to solve this problem.
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11. -/1 points My Notes Two charges q1-3 μC, q2 =-30 μC, are L = 19...
Two charges, so far apart, with a 3rd placed in the middle to find the minimum force
Two charges q1 = 5 µC, q2 = -30 µC, are L = 17 cm apart. A third charge is to be placed on the line between the two charges. How far from q1 should the third charge beplaced so that the net electric force on the third charge is minimized?
Two charges of q1 = 1.4 μC and q2 = −2.1 μC are d = 0.56...
Two charges of q1 = 1.4 μC
and q2 = −2.1 μC are
d = 0.56 m apart at two vertices of an
equilateral triangle as in the figure below.
(a) What is the electric potential due to the 1.4-μC
charge at the third vertex, point P?
(b) What is the electric potential due to the −2.1-μC
charge at P?
(c) Find the total electric potential at P.
(d) What is the work required to move a 3.8-μC charge
from...
Two charges, Q1= 4.00 μC, and Q2= 5.30 μC are located at points (0,-3.50 cm )...
Two charges, Q1= 4.00 μC, and Q2= 5.30 μC
are located at points (0,-3.50 cm ) and (0,+3.50 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (5.50 cm, 0), due to Q1 alone?
What is the x-component of the total electric field at P?
What is the y-component of the total electric field at P?
What is the magnitude of the total electric field at P?
Now let Q2...
Two charges, Q1= 3.10 μC, and Q2= 6.20 μC are located at points (0,-3.00 cm )...
Two charges, Q1= 3.10 μC, and Q2= 6.20 μC
are located at points (0,-3.00 cm ) and (0,+3.00 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (5.50 cm, 0), due to Q1 alone?
The electric field at position P due to charge Q1 is not
influenced by charge Q2. Therefore, ignore charge Q2 and apply
Coulomb's Law. Remember to convert all units to the SI unit
system.
You have...
Two charges, Q1= 2.70 μC, and Q2= 5.90 μC are located at points (0,-3.00 cm )...
Two charges, Q1= 2.70 μC, and Q2= 5.90 μC
are located at points (0,-3.00 cm ) and (0,+3.00 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (5.50 cm, 0), due to Q1 alone?
6.18×106 N/C
You are correct.
Previous Tries
What is the x-component of the total electric field at
P?
By the principle of linear superposition, the total electric
field at position P is the vector sum of...
Two charges, Q1= 2.20 μC, and Q2= 5.80 μC are located at points (0,-2.00 cm )...
Two charges, Q1= 2.20 μC, and Q2= 5.80 μC
are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (5.00 cm, 0), due to Q1 alone?
Tries 0/12
What is the x-component of the total electric field at P?
Tries 0/12
What is the y-component of the total electric field at P?
Tries 0/12
What is the magnitude of the total electric...
Two charges, Q1=2.90 μC, and Q2=5.30 μC are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in the figure.
Two charges, Q1=2.90 μC, and Q2=5.30 μC are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in the figure. What is the magnitude of the electric field at point P, located at (5.00 cm, 0), due to Q1 alone? The electric field at position P due to charge Q1 is not influenced by charge Q2. Therefore, ignore charge Q2 and apply Coulomb's Law. Remember to convert all units to the SI unit system. What is the x-component of the total...
Two charges, Q1= 2.50 μC, and Q2= 5.70 μC are located at points (0,-3.00 cm )...
Two charges, Q1= 2.50 μC, and Q2= 5.70 μC are located at points (0,-3.00 cm ) and (0,+3.00 cm), as shown in the figure. What is the magnitude of the electric field at point P, located at (6.50 cm, 0), due to Q1 alone? Tries 0/12 What is the x-component of the total electric field at P? Tries 0/12 What is the y-component of the total electric field at P? Tries 0/12 What is the magnitude of the total electric...
Two charges, Q1= 3.40 μC, and Q2= 5.10 μC are located at points (0,-3.50 cm )...
Two charges, Q1= 3.40 μC, and Q2= 5.10 μC
are located at points (0,-3.50 cm ) and (0,+3.50 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (6.50 cm, 0), due to Q1 alone?
5.61×106 N/C
You are correct.
Previous Tries
What is the x-component of the total electric field at
P?
By the principle of linear superposition, the total electric
field at position P is the vector sum of...
Two point charges, Q1 = -5.6 μC and Q2 = 1.8 μC , are located between...
Two point charges, Q1 = -5.6 μC and Q2 = 1.8 μC , are located between two oppositely charged parallel plates, as shown in (Figure 1). The two charges are separated by a distance of x = 0.45 m . Assume that the electric field produced by the charged plates is uniform and equal to E = 60000 N/C . Neglect the charge redistribution in plates. Calculate the magnitude of the net electrostatic force on Q1 and give its direction.
Two charges of q1 = 1.4 μC
and q2 = −2.1 μC are
d = 0.56 m apart at two vertices of an
equilateral triangle as in the figure below.
(a) What is the electric potential due to the 1.4-μC
charge at the third vertex, point P?
(b) What is the electric potential due to the −2.1-μC
charge at P?
(c) Find the total electric potential at P.
(d) What is the work required to move a 3.8-μC charge
from...
Two charges, Q1= 4.00 μC, and Q2= 5.30 μC
are located at points (0,-3.50 cm ) and (0,+3.50 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (5.50 cm, 0), due to Q1 alone?
What is the x-component of the total electric field at P?
What is the y-component of the total electric field at P?
What is the magnitude of the total electric field at P?
Now let Q2...
Two charges, Q1= 3.10 μC, and Q2= 6.20 μC
are located at points (0,-3.00 cm ) and (0,+3.00 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (5.50 cm, 0), due to Q1 alone?
The electric field at position P due to charge Q1 is not
influenced by charge Q2. Therefore, ignore charge Q2 and apply
Coulomb's Law. Remember to convert all units to the SI unit
system.
You have...
Two charges, Q1= 2.70 μC, and Q2= 5.90 μC
are located at points (0,-3.00 cm ) and (0,+3.00 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (5.50 cm, 0), due to Q1 alone?
6.18×106 N/C
You are correct.
Previous Tries
What is the x-component of the total electric field at
P?
By the principle of linear superposition, the total electric
field at position P is the vector sum of...
Two charges, Q1= 2.20 μC, and Q2= 5.80 μC
are located at points (0,-2.00 cm ) and (0,+2.00 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (5.00 cm, 0), due to Q1 alone?
Tries 0/12
What is the x-component of the total electric field at P?
Tries 0/12
What is the y-component of the total electric field at P?
Tries 0/12
What is the magnitude of the total electric...
Two charges, Q1= 3.40 μC, and Q2= 5.10 μC
are located at points (0,-3.50 cm ) and (0,+3.50 cm), as shown in
the figure.
What is the magnitude of the electric field at point P, located
at (6.50 cm, 0), due to Q1 alone?
5.61×106 N/C
You are correct.
Previous Tries
What is the x-component of the total electric field at
P?
By the principle of linear superposition, the total electric
field at position P is the vector sum of...
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