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The route followed by a hiker consists of three displacement vectors A with arrow, B with...

The route followed by a hiker consists of three displacement vectors A with arrow, B with arrow, and C with arrow. Vector A with arrow is along a measured trail and is 1550 m in a direction 23.0° north of east. Vector B with arrow is not along a measured trail, but the hiker uses a compass and knows that the direction is 41.0° east of south. Similarly, the direction of vector vector C is 40.0° north of west. The hiker ends up back where she started, so the resultant displacement is zero, or A with arrow + B with arrow + C with arrow = 0. Find the magnitudes of vector B with arrow and vector C with arrow.

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Answer #1

If the sum of three vectors is zero then the individual sums of their x and y components will also be zero.

Therefore

A_x + B_x + C_x = 0

by plugging all the values we get

1550cos(23) + Bsiri (41) + (_Ccos(40))-0 eq-1

and

A_y + B_y + C_y = 0

or

1550sin(23) + (-Bcos(41)) Csin(40)0 eq-2

There are two equations with two variables B and C

by solving both the equations we get

B 8828.4771 C-9423.4772

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