Question

Vector A with arrow has a magnitude of 141 units and points 33.0° north of west. Vector B with arrow points 69.0° east of north. Vector C with arrow points 14.0° west of south. These three vectors add to give a resultant vector that is zero. Using components, find the magnitudes of the following vectors.

a. Vector B

b. Vector C

Answer 1

Hi,

Question is all about resolving all three vectors into "x" and "y" components and then equating them.

I will attach the solution.

If any doubt, feel free to ask.

P.S. : A feedback is much appreciated.

Lex 59° 3 - > E 90 for resultant of all three nectors to be youo. y components: Ai sin 33 - 18 cos69° = 181 cost4o ... (1) 13 sin ogo - ² coss3° +18, sin 14° ..(2) x components :- À 1 = 141 put 1512b and 1²1=c 141 *0.54 + 6* 0.36 = Cx0.97 bx0.93 = 241 X 0.84 +CX0.24 .- (3) ---M 76.145) 76.14 + 0-36 b = 0.970 0.36b-0.97 CE -76.14 0.93b = 118.44 +0.24 C = 0.936 -0.24 C = 118.44 (5) x 0.24 - (6) X 0.97 - - 0.0866 -0.232C = -18.27 0.90 2/6 -0.282 CE 114.8268 -0.816 1 b= -133.1568 be 163 Similarly- Tox 138