Question

(ii) A particle undergoes simple harmonic motion with amplitude 0.2 m. Calculate the total distance the particle has covered at the end of 1.5 oscillations.

Answer 1

solution : ) amplitudo in sum is A= 0.2m total distance the particle has covered at the end of 1.5 oscillation is zero. amplitude A = 2.00m A=0.02m 81cm=0.01m. time period - 0.255 we know that acceleration of the body in sum is a - win here - - A = -0.02m and w = 27 so a = - (27 %-A) a = 12.63 m/s?

(6) equation of a progressive wave is y = 0.5 Sin (0.25% -50f) o We know that equation of a progressive wore is Y = Asin CK- wt) —♡ Compare equation 11) and (2) amplitude A = 0.5m wave number *=0.25 grad/m angulas frequency w = 50 rad's As we know that the wave propagation speed is [v: 200.0 m/s]