A particle undergoes simple harmonic motion with amplitude 25 cm and maximum speed 4.8 m/s. If a stopwatch is started when the particle is pulled to its maximum position and released, what is the formula for the position of the particle as a function of time?
angular frequency
w = v/ A = 4.8 / 0.25 = 19.2 rad/s.
now as we know
x = A cos ( wt)
x = 25 cos (19.2 t)
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