Question

TOOK TO LONG DONT SOLVE FIGURED IT OUT MYSELF

If you heat a 5.0 liter steel tank to 150.0 degree Fahrenheit that contains 101.2 grams of propane MW 44 grams /mole the pressure in the tank will be?

A. 1300 torr

B. 9.89 atm

C. 9.7 x 10 ³ mm of Hg

D. 195 lb/in ²

Answer 1

T= 150 °F (F-32 ) * (ISO - 32 ). . . T= 65.55°C T = (65.55 + 273.15)k T= 338.55k/ moles of propane = 2.3 mol mol = 101.2 fm 44 gr/mol n = 2.3 mol [v=5.0 litre! es P = 12.78 ahm Gas equation PV=ORT p=nRT P= 12.78 *760 mming p = 9717 mmHg P: (2-3 mol) *(00821 am.L )* ( 338.55k) molok 5.0L P = 9.7x 103 mm reg / TP= 12.78 atm