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14mL of 0.40M hydrochloric acid were added to a solution of an antacid. 7.7mL of 0.50M...

14mL of 0.40M hydrochloric acid were added to a solution of an antacid. 7.7mL of 0.50M sodium hydroxide were used to compensate for the excess of HCl. How many equivalents of excessive HCl were titrated?

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Answer #1

a number of moles of my = 0.40 mol/Lx 0.0142 -0.0056 mele Now number پا of moles of Naast = 0.5 mol/L x 0.0077 L = 0.00385 mo

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