Solution:- option d.
Region 1 x1; n1 = 12
x1 = 702, s1 = 326.8074
region 1 x2; n2 = 16
x1 = 637.75 , s2 = 185.6615
df = n1+n2-2 = 12+16-2 = 26
t = 1.706
99% confidence interval for the population difference mean
:
(x1-x2) +/- t*sqrt((s1^2/n1)+(s2^2/n2))
= (702-637.75)+/- 1.706*sqrt((326.8074^2/12)+(185.6615^2/16))
= -115.12 , 243.62
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