Question

Calculate the work in kilojoules done during a synthesis of ammonia in which the volume contracts from 7.7 L to 4.5 L at a constant external pressure of 43 atm . Express your answer using two significant figures.

Answer 1

The complete calculation of the work done is given as below:-

It is given that, Initial volume (VI) = 7,7L and Final volume (V2) =4.52 Pressure (external) Pext = 43 atm Then du= Vzovi = (4.5.7.7) L = -3.2L So, dv = -3.2L - 0 since, IL -103 Then dv=-3.2 x 103 m3 - ③ atm = 1:01325 x 105 N/m2 Then 43 atm = = 43*1.01325 xlo > Nime . 43 atm

so, p= 43. 57 xlos N/m² - ③ Then the work done is given by: - wa - Pext dv = (43.57X10 N/m2) x (-3.2x1=3 m3) on W= + 139.424 x 102 J = 13.94 24 x103 g since, IKJ = 1000 J Then work done is given by :- W = + 13.9424 x 1037= 13.94 24 kJ on Tw=+13.94 KJ) Positive sign due to work done on the system in contraction,