Question

Chapter 2, Section 3, Exercise 107 Percent Obese by State Computer output giving descriptive statistics for the percent of the population that is obese for each of the 50 US states, from the USStates dataset, is given in the table shown below. Since all 50 US states are included, this is a population, not a sample Descriptive Statistics: Obese Variable N N MeanSE Mean StDev Minimum Median3 Maximum Obese 50 028.766 0.4763.369 21.300 26.375 29.400 31.150 35.100 Percent of the population that is obese by state Click here for the dataset associated with this question. (a) What are the mean and the standard deviation? SHOW HINT LINK TO TEXT

Answer 1

TOPIC:Z scores and Empirical rule.

From the dataset as follows given the summary required output of the obsenvations are variable N N mean staer Minimum Maximum obbese 50 o 28.766 3.36 21.300 35.100 @ So, here i (mean) = /28.766 7. o (sd) = [3.369 %. and O Largest value = maximum value = 35.100. 35.100-ml the largest value is a 32 u z -score for 35.100- 28.766 3.369 = 1.880 & isty The maximum of 35.1 4. obsese is [1.880 standard deviations above the mean. T: The z-score is 2-sure for the positive and largest value = 1.8801

> Again - the smallest value. = Minimum value = 21.300. i 2-score for the smallest value is - 21.300M O 21.300-28.766 3.369 = [-2.216) The minimum of 21.3 %. obsese is [2.216) standard deviations below the mean. with The z-score is negative magnitude a 2.216 a bello shaped . By the Empirsical rule of distribution, approximatety I- 68 r. data falls within ii) 957. & & & and line 99.7%, in " (uno, uro); (M-26, M+20); (M-36, M +36)

Here = 28.766 (/. o = 3.369 (~2. So, since the distrat distribution is bell-shaped by the Empirsical rule, 95 7. of the data values falls within the interval → I M-20 " to [ ut 20 r. 128.766-2 x 3.369 % to. 28.766 +2X3.369/ = ( 22.028 7. to (35.504 %. The world 22.028 %.. to 35.504 7. Answer