Question

of Data, 2e PRINTE Cs for the percent of the population that is obese for each of the 50 US states, from the USStates dataset, is given in the table shown below. S . Descriptive Statistics: Obese о N* Variable Мaximum Mean SE Mean Median StDev Minimum 50 28.766 3.369 29.400 35.100 0 0.476 21.300 26.375 31.150 Obese Percent of the population that is obese by state n this question. d deviation?

Answer 1

(b)

(i)

$\mu$ = 28.766

$\sigma$ = 3.369

The largest value: 35.100

Z score = (35.100 - 28.766)/3.369

          = 1.880

So,

Answer is:

Z score

1.880

(ii)

The maximum of 35.1% obese is 1.880 standard deviations above the mean.

(iii)

The smallest value: 21.300

Z score = (21.300 - 28.766)/3.369

          = - 2.216

So,

Answer is:

Z score

- 2.216

(iv)

The minimum of 21.3% obese is 2.216 standard deviations below the mean.

(c)

By 68 -95-99.7 Rule, 95% of the data lies between $\mu -2\sigma$ to $\mu +2\sigma$

i.e., $\mu -2\sigma =28.766 +(2\times 3.369)=28.766-6.738=22.028$

$\mu +2\sigma =28.766 +(2\times 3.369)=28.766+6.738=35.504$

So,

Answer is:

The interval is

22.028

% to

35.504

%