Mg(OH)2 Ksp = 5.61 x 10^ -12 M
99.9 % Mg2+ of 0.053 = ( 99.9/100) x 0.053 = 0.052947 , [Mg2+] left free = 0.053-0.052947 = 0.000053 M
now Ksp = [Mg2+] [OH-]^2
5.61x 10^ -12 = 0.000053 [OH-]^2
[OH-] = 1.06 x 10^ -7 M
Thus minimum hydroxide needed = 1.06 x 10^ -7 M
No sodium ions will get precipitated
No Calcium ions will get precipitated
Na+=0.47 M, Mg2+=0.053 M, Ca2+=0.010 M magnesium is isolated from seawater by adding a strong base...
The magnesium and calcium ions present in seawater ([Mg2+] = 0.059 M and [Ca2+] = 0.011 MM) can be separated by selective precipitation with KOH. Part A If the concentration of Mg2+ in the solution were 0.036 M, what minimum [OH−] triggers precipitation of the Mg2+ ion? (Ksp=2.06×10^−13) Express your answer to two significant figures and include the appropriate units.
The magnesium and calcium ions present in seawater (Mg2+] = 0.059 M and (Ca2+] = 0.011 M) can be separated by selective precipitation with KOH. If the concentration of Mg2+ in the solution were 0.018 M, what minimum (OHtriggers precipitation of the Mg2+ ion? (Ksp = 2.06 x 10-13.) Express your answer to two significant figures and include the appropriate units. 03 O ? Value M
The magnesium and calcium ions present in seawater ([Mg2+] = 0.059 M and (Ca2+] = 0.011 M) can be separated by selective precipitation with KOH. Part A If the concentration of Mg2+ in the solution were 0.021 M. what minimum (OH-] triggers precipitation of the Mg2+ ion? (Ksp = 2.06 x 10-13.) Express your answer to two significant figures and include the appropriate units. | НА w ? Value Units Submit Previous Answers Request Answer
enodic Table The magnesium and calcium ions present in seawater ([Mg2+] = 0.059 M and (Ca2+] = 0.011 M) can be separated by selective precipitation with КОН. You may want to reference (Pages 775 - 778) Section 17.6 while completing this problem. Part A If the concentration of Mg2+ in the solution were 0.018 M, what minimum (OH) triggers precipitation of the Mg2+ ion?( Ksp = 2.06 x 10-13.) Express your answer to two significant figures and include the appropriate...
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Experiment 8 Name: Double Replacement Reactions Background: Some reactions have the net effect of causing the cation of cach reactant to trade places, forming a compound with the other anion. These reactions are known as double replacement reactions. In the example below (unbalanced equation), the barium and sodium cations switch places so that barium forms a product with sulfate while sodium forms...