10.
This is a case of completely inelastic collision:
Using momentum conservation in this case:
Pi = Pf
Mb*Ub + Mw*Uw = (Mb + Mw)*V
Ub = initial speed of bullet = ?
Uw = initial speed of wood = 0 m/sec
V = final speed of wood + bullet = 13 m/sec
Mb = 5 gm = 0.005 kg
Mw = 200 gm = 0.2 kg
So Using these values:
0.005*Ub + 0.2*0 = (0.005 + 0.2)*13
Ub = (0.005 + 0.2)*13/0.005 = 533 m/sec = Initial speed of bullet
11.
Again Using momentum conservation:
Pi = Pf
Mb*Ub + Ms*Us = Mb*Vb + Ms*Vs
Ub = initial speed of superball = ?
Us = initial speed of student = 0 m/sec
Vb = final speed of superball = -20 m/sec (See that ball bounces back, So direction will be opposite of initial direction)
Vs = final speed of student = +1.3 m/sec
Mb = 0.5 kg
Ms = 40 kg
Using these values:
0.5*Ub + 40*0 = 0.5*(-20) + 40*1.3
Ub = (0.5*(-20) + 40*1.3)/0.5
Ub = 84 m/sec = initial speed of superball
Please Ask rest of the questions as a new question, I will be happy to help. As HOMEWORKLIB RULES guideline I've answered one question. (In this case 2)
Please Upvote.
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