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QUESTION 11 Calculate the pH for an aqueous solution of acid that contains 2.15 x 10-3 M H30 at equilibrium. A. 4.65x 10-12 B
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Answer #1

(30+] = 2.15x15 3M pH = -log ((H₂O + ] pH = -log ( 2.15x10²) pha 2.67 12. 1 2 c (on pou= = 2.15 x 103 m -log (Con-l) - por= -

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