10)
[H+] = [HCl] = 0.015 M
use:
[OH-] = (1.0*10^-14)/[H+]
[OH-] = (1.0*10^-14)/(0.015)
[OH-] = 6.67*10^-13 M
use:
pH = -log [H+]
= -log (0.015)
= 1.82
Answer:
[H+] = 0.015 M
[OH-]= 6.67*10^-13 M
pH = 1.82
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