Question

A lobster tank in a restaurant is 0.5 m long by 0.25 m wide by 50 cm deep. Find the water forces
on the bottom of the tank: Force =
on each of the larger sides of the tank: Force =
on each of the smaller sides of the tank: Force =

include units for each, and use g = 9.8m/s². The mass density of water is 1000 Kg/m^3. Do (mass density)*(volume)*(g) to get force in Newtons.Mass density and g are constant. Volume is (cross sectional area)*(depth)

Answer 1

1)F=mg = dV g = 1000*(.5*.25*.5) * 9.8 =612.5 N
2) 1/2 * d g * A = .5 * 1000 * 9.8 * (.5* .5) = 1225 N
3)1/2 * d g * A = .5 * 1000 * 9.8 * (.5 * .25) = 612.5 N

Answer 2

1)F=mg = dV g = 1000*(.5*.25*.5) * 9.8 =612.5

2) 1/2 * d g * A = .5 * 1000 * 9.8 *.5* .5* = 1225

3)1/2 * d g * A = .5 * 1000 * 9.8 *.5* .25* = 612.5