Question

Name: Anilun G.._class: Date: LAB inal 1/2 Measured numbers and significant figures in calculations - Mese were all measured numbers, what would the answers to these equations be with the right number of significant figures? Show the answer before and after adjusting for significant figures. 1) 3.461728 + 14.91 +0.980001 + 5.2631 = 2) 23.1 +4.77 + 125.39 + 3.581 = 3) 22.101 -0.9307 = 4) 0.04216 - 0.0004134 = 6) (3.4617 x 107) - (5.61 x 10) = 7) [(9.714 x 109) (2.1482 x 10 9] + 3.20 = 8) [(561.00) (34,908) (23.0112)] + 4.1212 = 9) [(561.0) (34,908) (23.0112)] + 4.1212 = 10) [(561) (34,908) (23.0112)] + 4.1212 =

Answer 1

duy) Caleulation centrelee ito cooweet sign figs. * Additing que debtsueting. -) Determine the leaxt # of decimal places in problem I round ito the number of decimal places. Ex. 1000278 + 105g = 8.5279 = 8.54 should 3 derece be Place 8.5g @ Meltiplying and Diuiding - Determine the lest #of sign figs in puoblem a round to that of sign figs Ex: 10.0279 + 1050ml = 6.6847g/ml = 6068914 5 Sigf. 3 sig fig 6.68 g/ml Cshould be

ma Solution 72 deeplace O. 3.4617 28+140914 0.980001 +5•263) = 24.61 oldec pace 2381 +4677 +125.39 +3.581= 156.8 © » 3 dcchae 5 dec place 3 signfigur 3 signfigur © 32.701 -0.9307 = 21.170 Ⓡ 0.04216 - 0.0004134 = 0.04175 © (3.4617 xro)(5.612164) = 6017 X10'0 © [ 69. 714 X105)(2.1492810397# 3.20 – 6.52x1024 assignfiger 8) 7 (567.00) (34,908)(23.0124.1212 = 109.35 X10* usign figur 9) [(561.07(34,98) (23.010)74 .1212 = 109.3810* 3 signfigur. lo) (1561) (34,908) (23.0112)7:401212 = 10.9 X 106 Thank your