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WWUUUUUUULA On-Line Course 2. A proton pt is accelerated from rest through a pair of parallel plates as shown below. Its spee

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Answer #1

a)

using energy conservation

0.5 m v^2 = qV

0.5* 1.67* 10^-27* (1.5* 10^6)^2 = 1.6* 10^-19 V

V = 11742.2 V

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b)

using conservation of energy

k q1 q2 / r = q1 V

9* 10^9* 2.4* 10^-6 / r = 11742.2

r = 1.8395 m

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