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(a) Your pendulum clock which advances 1.0 s for every complete oscillation of the pendulum is running perfectly on Earth atPlease answer the question for part B.

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Answer #1

If then- I be the Time period length of in earth, the Te= pendulam 2 whese ge = 9.80 m/sh. Time period in moon, Tmaanse whereSo I sec. in earth is similas to four sec. in moon 2.437 tous 18-2hs in earth = 18-2 x60 san x60 see. In moon - see 18.2x 60

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Please answer the question for part B. (a) Your pendulum clock which advances 1.0 s for...
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