A pendulum clock is accurate on earth, where the period of its
pendulum is 1.00 s.
(a) Find its period on the moon, where gravitational acceleration
is 1.6 m/s2.
(b) During a 2 h interval, what would be the elapsed time shown on
the clock?
g value on earth varies from location to location. I'll assume a value of 9.8 m/s
(a) the period of the pendulum is T= 2TTsqrt(L/g) - only depends on length and gravity T' = 2TTsqrt(L/g') = T sqrt(g/g') = 1 s * sqrt( 10/1.6) = 2.5 s (b) so the clock measures 1 second on the moon every 2.5 seconds in real time so in 3600 s it only measures... 3600/2.5=1440 s =24 minutes
A pendulum clock is accurate on earth, where the period of its pendulum is 1.00 s....
A pendulum clock is accurate on earth, where the period of its pendulum is 1.00 s. (a) Find its period on the moon, where gravitational acceleration is 1.6 m/s2. (b) During a 2 h interval, what would be the elapsed time shown on the clock?
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