Question

1. If placed at the surface of Earth, a physical pendulum has a period of 1.8...

1. If placed at the surface of Earth, a physical pendulum has a period of 1.8 seconds. What will be the period of the same pendulum at the surface of the Moon (gMoon = 1.62 m/s2)?

The period at the Moon's surface, T =  Units in s

2. The same pendulum is placed at the surface of an unknown planet X. What is the free fall acceleration at the surface of this planet if the pendulum has a period of 1.17 sec?

The free fall acceleration at the planet X, gX =  Unit in m/s2

3. If the pendulum consists of a mass attached to a string of an effective length L, find this length.

The effective length of the pendulum, L = Unit in m

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Answer #1

Ansi we know Te 27 وا۔ we have. bliven Tearth 581 = wouu Iman 9mon 1.62 2x 2x man Teath geath Tmon 171.62 x/9,8 9,8 1.8 126-2week 33 o (1.538)² = 9x 9-8 9.8*2.366 gx gx = 23,195 m/s² Ž eliven Tearth = 1.85 geant Auth = 9.8 m/s2 is T= 20 % 1.8-25 4.3

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