A simple pendulum 1= 40 cm is placed on the surface of the moon. The period...
1. If placed at the surface of Earth, a physical pendulum has a period of 1.8 seconds. What will be the period of the same pendulum at the surface of the Moon (gMoon = 1.62 m/s2)? The period at the Moon's surface, T = Units in s 2. The same pendulum is placed at the surface of an unknown planet X. What is the free fall acceleration at the surface of this planet if the pendulum has a period of 1.17...
Consider an object of mass 60 kg on the surface of the Moon, which has a mass of 7.3 x 1022 kg and a radius of 1740 km. Calculate the gravitational force experienced by the object due to the Moon Note: you may find the following information useful -- the universal gravitational constant is 6.67x10-11 Nm2/kg2 3.2 N 0 9.8 N O 11.6N O 588.0 N O 96.5 N
1. How much is the period of 1=1.00 m long pendulum on the Moon (g = 1.600 m/s2) 4.97 sec. 2. On a planet X pendulum of the length 0.500 m makes 50.0 oscillations in 1.00 min. Find the acceleration of gravity on the planet X. g = 13.7 m/s2. 3. Find the period of small oscillations of a meter stick suspended by its end near Earth surface (assume g=9.800 m/s2). Notice that this is not a simple pendulum but...
Suppose that Nolan Ryan stands on the surface of the moon and throws a baseball horizontally. If the baseball has a high enough speed and does not strike any mountain,it can orbit around the moon and, after completing the orbit, strike Nolan from behind. The mass of the moon is mm = 7.35×1022 kg, and its radius is rm = 1740 km. Thegravitation constant G = 6.67×10-11 Nm2/kg2.1)Find the speed at which Nolan must throw the ball for such a...
10. An astronaut is standing on the surface of a planetary satellite that has a radius of 1.74 x 106 m and a mass of 7.35 x 1022 kg. An experiment is planned where a projectile needs to be launched straight p from the surface. What must be the minimum initial speed of the projectile so it will reach a height of 2.55 x 106 m above this satellite's surface? G = 6.67 x 1011 kg2
A simple pendulum on the surface of the Earth has period T. On a different planet, the same pendulum has period 27. The free-fall acceleration on this planet is 04g O g/4 O2g O g/2
What is the period (in s) of a simple pendulum of length 0.12 m and mass 0.31 kg near the surface of a planet where the gravitational acceleration is 11 m/s2? Enter a number with 2 digits behind the decimal point..
An undiscovered planet, many light-years from Earth, has one moon, which has a nearly circular periodic orbit. If the distance from the center of the moon to the surface of the planet is 2.270 × 105 km and the planet has a radius of 3.150 × 103 km and a mass of 6.55 x 1022 kg, how long (in days) does it take the moon to make one revolution around the planet? The gravitational constant is 6.67 x 10lN-m2/kg2 T-0.88125...
Three identical masses of 570 kg each are placed on the x axis. One mass is at x1 = -150 cm , one is at the origin, and one is at x2 = 350 cm . Part A What is the magnitude of the net gravitational force Fgrav on the mass at the origin due to the other two masses? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 . Express your answer in Newtons.
Three identical masses of 570 kg each are placed on the x axis. One mass is at x1 = -150 cm , one is at the origin, and one is at x2 = 350 cm . Part A What is the magnitude of the net gravitational force Fgrav on the mass at the origin due to the other two masses? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 . Express your answer in Newtons.