Homework Answers
Hi Dear Friend, we have to use below formula
Q = m x Cs x ΔT
where m = mass of water = 150.1 g;
Cs = specific heat = 4.18 J/g.0C:
ΔT = temp. difference = (T - 24.2 0C);
Q = Heat absorbed or Released = 950. J
ΔT = Q / (m x Cs) = 950 J / (150.1 g x 4.18 J/g.0C) = 1.51414208709 0C
ΔT = T - 24.2 0C = 1.51414208709 0C
T = 1.51414208709 0C + 24.2 0C = 25.7141420871 ~ 25.7 0C
Answer: Final Temperature = 25.7 0C
Hope this helped you!
Thank You So Much! Please Rate this answer as you wish.("Thumbs Up")
Add Answer to:
Submit Question 28 of 50 What is the final temperature of 150.1 g of water (specific...
Question 30 of 50 Submit A 90.0 g piece of metal, initially at 98.6°C, is placed...
Question 30 of 50 Submit A 90.0 g piece of metal, initially at 98.6°C, is placed into 120.0 g of water initially at 24.3°C. If the final temperature of the water is 34.0°C, what is the specific heat of the metal? (The specific heat of water is 4.18 J/g °C). J/g.°C 1 2 3 C +/- : 0 x 100
Question 29 of 50 Submit 5.21 g of MgSO4 is placed into 100.0 mL of water....
Question 29 of 50 Submit 5.21 g of MgSO4 is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate AH, in kJ/mol, for the dissolution of MgSO4 (The spe- cific heat of water is 4.18 J/g. *C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water. kJ/mol 1 2 3 C +/- : 0 x 100
Question 44 of 50 Submit 3.15 mol of an unknown solid is placed into enough water...
Question 44 of 50 Submit 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases by 19.21°C. Calculate AH for the dissolution of the unknown solid. (The specific heat of the solution is 4.18 J/g.°C and the density of the solution is 1.20 g/mL). kJ/mol 1 2 3 C +/- : 0 x 100
What is the final temperature when a 10.0 g sample of water is heated with an...
What is the final temperature when a 10.0 g sample of water is heated with an input of 20.0 kJ starting at 10.0°C? You might need the following information for water: specific heat H2O(s): 2.09 J/g°C specific heat H2O(l): 4.18 J/g°C specific heat H2O(g): 1.84 J/g°C heat of fusion: 6.09 kJ/mole heat of vaporization: 40.7 kJ/mole Answer choices are: 488°C 273°C 89.0°C 100.°C It said 488 was wrong.
3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from...
3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0°C to 65.0°C. The specific heat of water is 4.18 J/gºC. Show your work Final Answer 4. Aluminum metal has a specific heat of 0.901 J/g C. How much heat is transferred to a 6.75 g piece of aluminum initially at room temperature, 20.0°C, when it is placed into boiling water? The temperature of boiling water is 100°C. Show your work Final Answer 5....
3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0°C to 65.0'C. The specif...
3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0°C to 65.0'C. The specific heat of water is 4.18 J/gºC. Show your work Final Answer 4. Aluminum metal has a specific heat of 0.901 J/g C. How much heat is transferred to a 6.75 g piece of aluminum initially at room temperature, 20.0°C, when it is placed into boiling water? The temperature of boiling water is 100°C. Show your work Final Answer 5....
1. 50 mL of water at 51.9°C were mixed with 50 mL of water at 23.2°C...
1. 50 mL of water at 51.9°C were mixed with 50 mL of water at 23.2°C in a calorimeter also at 23.2°C. The final temperature was 33.1°C. Assuming that neither the density of water nor its specific heat capacity change with temperature, calculate the total heat capacity of the calorimeter. (density of water = 1.00 g mlº', specific heat capacity=4.18 J g?K=) 2. When 5.00 g of NaOH(s) are added to 100 g of water (using the same calorimeter as...
A 125 g quantity of water is initially at a temperature of 21.34 °C. A 1925...
A 125 g quantity of water is initially at a temperature of 21.34 °C. A 1925 J quantity of heat flows into the water. What is the final temperature of the water? The specific heat capacity of water is 4.18 J/g/°C. Select one: O A. 21.61 °C O B. 32.53 °C O C. 17.66 °C O D. 36.74 °C O E. 25.02 °C
Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0...
Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0 to 65.0 degrees C. The specific heat of water is 4.18 J/gC
50 mL of water at 51.9°C were mixed with 50 mL of water at 23.2°C in...
50 mL of water at 51.9°C were mixed with 50 mL of water at 23.2°C in a calorimeter also at 23.2°C. The final temperature was 33.1°C. Assuming that neither the density of water nor its specific heat capacity change with temperature, calculate the total heat capacity of the calorimeter. (density of water = 1.00 g mL"', specific heat capacity= 4.18 J g'K:')
Question 30 of 50 Submit A 90.0 g piece of metal, initially at 98.6°C, is placed into 120.0 g of water initially at 24.3°C. If the final temperature of the water is 34.0°C, what is the specific heat of the metal? (The specific heat of water is 4.18 J/g °C). J/g.°C 1 2 3 C +/- : 0 x 100
Question 29 of 50 Submit 5.21 g of MgSO4 is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate AH, in kJ/mol, for the dissolution of MgSO4 (The spe- cific heat of water is 4.18 J/g. *C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water. kJ/mol 1 2 3 C +/- : 0 x 100
Question 44 of 50 Submit 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases by 19.21°C. Calculate AH for the dissolution of the unknown solid. (The specific heat of the solution is 4.18 J/g.°C and the density of the solution is 1.20 g/mL). kJ/mol 1 2 3 C +/- : 0 x 100
3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0°C to 65.0°C. The specific heat of water is 4.18 J/gºC. Show your work Final Answer 4. Aluminum metal has a specific heat of 0.901 J/g C. How much heat is transferred to a 6.75 g piece of aluminum initially at room temperature, 20.0°C, when it is placed into boiling water? The temperature of boiling water is 100°C. Show your work Final Answer 5....
3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0°C to 65.0'C. The specific heat of water is 4.18 J/gºC. Show your work Final Answer 4. Aluminum metal has a specific heat of 0.901 J/g C. How much heat is transferred to a 6.75 g piece of aluminum initially at room temperature, 20.0°C, when it is placed into boiling water? The temperature of boiling water is 100°C. Show your work Final Answer 5....
1. 50 mL of water at 51.9°C were mixed with 50 mL of water at 23.2°C in a calorimeter also at 23.2°C. The final temperature was 33.1°C. Assuming that neither the density of water nor its specific heat capacity change with temperature, calculate the total heat capacity of the calorimeter. (density of water = 1.00 g mlº', specific heat capacity=4.18 J g?K=) 2. When 5.00 g of NaOH(s) are added to 100 g of water (using the same calorimeter as...
A 125 g quantity of water is initially at a temperature of 21.34 °C. A 1925 J quantity of heat flows into the water. What is the final temperature of the water? The specific heat capacity of water is 4.18 J/g/°C. Select one: O A. 21.61 °C O B. 32.53 °C O C. 17.66 °C O D. 36.74 °C O E. 25.02 °C
50 mL of water at 51.9°C were mixed with 50 mL of water at 23.2°C in a calorimeter also at 23.2°C. The final temperature was 33.1°C. Assuming that neither the density of water nor its specific heat capacity change with temperature, calculate the total heat capacity of the calorimeter. (density of water = 1.00 g mL"', specific heat capacity= 4.18 J g'K:')
Most questions answered within 3 hours.
-
1. When a nearsighted person looks at an object that is in the
distance with their...
asked 2 minutes from now -
QUESTION 8
Both of these statements will store the same value in the
variable $number
$number...
asked 21 minutes ago -
The price of 1 lb of potatoes is $1.75. If all the potatoes sold
today at...
asked 1 hour ago -
Garcia Company issues 20.00%, 15-year bonds with a par value of
$470,000 and semiannual interest payments....
asked 1 hour ago -
In C++ Programming, Try using loops only.
This lab demonstrates the use of the While Loop...
asked 2 hours ago -
Effect of DCMU and sodium azide on Chlamydomonas? We did an
experiment where we had Chlamydomonas...
asked 2 hours ago -
1a) According to the ideal gas law, _______________.
a. a gas has infinite volume at absolute...
asked 4 hours ago -
Oakdale Fashions, Inc. had $245,000 in 2018 taxable income.
Using the tax schedule in Table 2.3...
asked 4 hours ago -
The marketing class at CSUS had an average score of 150. An
educational analyst determined that...
asked 5 hours ago -
Justin Case has purchased a $250 000 home by putting 20 % down
and taking out...
asked 6 hours ago -
1. In a labor market, marginal cost for a firm is
____________.
a. recruiting cost
b....
asked 6 hours ago -
On January 1, 2019, ABC Company issued $60,000,000 of 20-year,
10.5% bonds when the market rate...
asked 7 hours ago