Question

A bloce & denr ty peo Hostfa down in a fud dmsts TPhe block 1 has heupht H 6.0 Cm Ki the black subaa The By what destt ) TP bock is fally subonase fons the Gaohehor y

Answer 1

let
rho_block = 800 kg/m^3
rho_fluid = 1200 kg/m^3

a) let A upper and lower face of the block.

in the equilibrium net force acting on the block = 0

B - m*g = 0

rho_fluid*V_displacedfluid*g - rho_block*V_block*g = 0

rho_fluid*V_displacedfluid*g = rho_block*V_block*g

rho_fluid*V_displacedfluid = rho_block*V_block

1200*A*h = 800*A*H

==> h = 800*H/1200

= 800*6/1200

= 4.0 cm <<<<<<<<<---------------Answer

b) when block is full submerged,

Fnety = B - m*g

m*a = rho_fluid*V_displcedfluid*g - rho_block*V_block*g

rho_block*V_block*a = rho_fluid*V_block*g - rho_block*V_block*g

a = rho_fluid*g/rho_block - g

= 1200*9.8/800 - 9.8

= 4.9 m/s^2 <<<<<<<<<----------------Answer