a)
At equilibrium:
AgI <----> Ag+ + I-
s s
Ksp = [Ag+][I-]
8.3*10^-17=(s)*(s)
8.3*10^-17= 1(s)^2
s = 9.11*10^-9 M
Answer: 9.11*10^-9 M
b)
NaI here is Strong electrolyte
It will dissociate completely to give [I-] = 0.02 M
At equilibrium:
AgI <----> Ag+ + I-
s 2*10^-2 + s
Ksp = [Ag+][I-]
8.3*10^-17=(s)*(2*10^-2+ s)
Since Ksp is small, s can be ignored as compared to 2*10^-2
Above expression thus becomes:
8.3*10^-17=(s)*(2*10^-2)
8.3*10^-17= (s) * 2*10^-2
s = 4.15*10^-15 M
Answer: 4.15*10^-15 M
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