A golfer puts her golf ball straight toward the hole. The ball's initial velocity is 3.97...
A golfer puts her golf ball straight toward the hole. The ball's initial velocity is 3.97 m/s, and it accelerates at a rate of -0.6 m/s2. What is the maximum distance that the golfer can be from the hole in order to make it? Give your answer in meters.
Homework Answers
using 3rd equation of motion
v^2 = u^2 + 2 a d
for maximum distance, v = 0 m/s
0 = 3.97^2 + 2* (-0.6)* d
d = 13.13 m
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do comment in case any doubt, will reply for sure Goodluck
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