Question

Suppose a golfer hits a ball with a velocity of 40 m/s at an angle of 30 degrees to the horizontal. The projectile model can be used to answer some questions about what will happen to the ball later during its flight.

a) where will the ball be 2 seconds later?

b) what is the greatest height the ball will reach?

c) if the golf ball is hit in the direction of a 12 meter tree which is 80 meters from the golfer, will the ball pass over the tree or hit it?

Answer 1

usin 30 : 1130 tol | vººdo a) veretical velocity: visin30*8 ms 2 400 m/= 20m/s. horizontal velocity 2 V.49s 300 ml 40x V3 - 34.64 ms.; After area. Shorizontal distance = 69.282m. vertical destanice = 40 m.. b) Greatest height Ha visina 30 2g 40*x sin 30 249.8 - 2014 m. c) Horizontal distance of the tree 280m the time taken to cover this horizontal distance 80 16:30 The Time taken for attaining max height: (i.e. to reath. H) =. Usin 30°, 40449 : 2,04 sec 9.0 १४ . which shows that after 2.889 sec . it will start descending and a .: the height descendid = gx (2.809–2-04) = 0.3534 m

its height =CH-0.3531) m 20:0546m which shows that it will pass over the tree