According to the question given,
1) Probability of a person using cell phone as a driver= (Total people using cell phone as a driver)/( Total number of people)
=305/755 = 0.4039 = 40.4 % ( Option C)
2) Probability of a person getting speeding violation = (Total people with speeding violation last year)/ (Total people using cell phone as a driver)
= 25/305 = 0.0819 = 8.2% ( Option D)
3) P(A)= Speeding violation last year= (Total people with speeding violation)/ (Total number of people)
= 70/755 = 0.0927 =9.27%
Therefore, P(Ac)= 100%- 9.27% = 90.73% = 90.7% (Option B)
4) Probability that a randomly selected person did not use phone as a driver = (Probability of not using a cell phone as driver)/ (Total number of people)
= 450/755 =0.596
Probability that a randomly selected person had no speeding violations last year= (People with no speeding violation last year)/ (Total People)
= 685/755 = 0.907
Now, Probability that a randomly selected person did not use phone as a driver or had no speeding violations last year= Probability that a randomly selected person did not use phone as a driver + Probability that a randomly selected person had no speeding violations last year
=0.596+0.907 = 1.503 (Option C)
PROBLEM A Suppose a study of speeding violations and drivers who use cell phones produced the...