Question

The IUPAC name for a carboxylic acid is based on the name of the hydrocarbon with the same number of carbon atoms. The ending -oic is appended, as in ethanoic acd, which is the IUPAC name for acetic acid, CH3COOH Give the RUPAC name for each of the following acids (Figure 1) Part A O carbonoic acid O methanoic acid O methyloic acid O methenoic acid Request Answer Submit Part B propanoic acid O isopropanoic acid butanoic acid isobutanoic acid Request Answer Submit Figure 1 of 1 Part C O 3-methylpentanoic acid O 3-methenepentanoic acid (a) HCOH O 3-methanebutanoic acid (b) CH CH CH COH O 3-ethylbutanoic acid (c) CH,CH-CHCH-COH Request Answer Submit CHS Provide Feedback

Answer 1

Only one carbon is present hence rootword is 'meth" HOH Methanoic acid b) NOH butanoic acid Four carbons are present hence rootword is 'but" longest carbon chain has five carbons with a methyl group at 3rd carbon and hence prefix is '3-methyl rootword is 'pent" 3-methylpentanoic acid

The IUPAC name of the any compound contains 3 parts prefix+ rootword + suffix Prefix = any substitutents rootword = longest chain containing most number of carbons if the chain contains 1 carbon = meth 2 carbon = eth 3 carbon = prop 7 carbon = hept 4 carbon = but 8 carbon = oct 5 carbon = pent 9 carbon = non 6 carbon = hex and so on Suffix = if the compound contains single bond (C-C) only then suffix 'ane double bonds (C=C) 'ene triple bonds 'yne For selecting prefix numbering, the substituents numbers has to be given in such way that the sum of the all substituents should be as less as possible. For selecting rootword chain, the chain with more number of carbons has to be selected In all the given compounds alkanes are present, hence the suffix is 'ane' in all the four compound For all the compounds, blue coloured part of the name is prefix. red coloured part of the name is rootword and pink coloured part of the name is suffix