The solubility product of BaSO4 is 1.08 x 10-10 in water. Calculate how much of the...
Calculate the solubility of BaSO4 (a) in pure water and (b) in a solution in which [SO42-) = 0.285 M. Ksp (BaSO4) = 1.1 x 10-10 Solubility in pure water = Solubility in 0.285 M ,2- - D M Submit Show Approach Show Tutor Steps
Use the molar solubility, 1.08 x 10- M, in pure water to calculate Kp for BaCrO4 Express your answer using three significant figures. IVO A O ? K = Submit Request Answer
Part A Use the molar solubility, 1.08 x 10-5 M in pure water to calculate Ksp for BaCrO4 Express your answer using three significant figures. Y AL OO ? Ksp = Submit Request Answer Part B. Use the molar solubility, 1.55 X 10' M in pure water to calculate Ksp for Ag, SO3 Express your answer using three significant figures. AED O ? Ksp = Submit Request Answer Part C Use the molar solubility, 2.22 x 10-8 M in pure...
Calculate the solubility of BaSO4 jn 4 M HCl I know that the solubility of BaSO4 is 1.1*10-10 in water How do i approach this problem?
At 25 0C the solubility product constant, Ksp, for strontium sulfate, SrSO4, is 7.6 x 10-7. The solubility product constant for strontium fluoride, SrF2, is 7.9 x 10-10. (a) What is the molar solubility of SrSO4 in pure water at 25 0C? (b) What is the molar solubility of SrF2 in pure water at 25 0C? (c) An aqueous solution of Sr(NO3)2 is added slowly to 1.0 litre of a well-stirred solution containing 0.020 mole F- and 0.10 mole SO42-...
How much greater is the molar solubility of strontium chromate (Ksp = 3.6 x 10-5) in pure water than it is when added to a solution that is 0.177 M in sodium chromate (Na2CrO4)? You may assume complete dissociation of the sodium chromate.
Calculate the molar solubility of silver chromate in pure water. Ksp = 1.12 x 10¯12
If the solubility product of scandium(III) fluoride, ScF3, in pure water is 1.0 x 10-18, What is the solubility of ScF3 a. 1.0 x 10-18 M b. 1.4 x 10-5 M c. 6.2 10-6 M d. 2.0 x 10-4 M e. 2.0 10-10 M
ksp=Ni(OH2)-->5.48*10^-16 Calculate the solubility at 25 °C of Ni(OH), in pure water and in a 0.0030 M NaOH solution. You'll find K, data in the ALEKS Data tab. Round both of your answers to 2 significant digits, solubility in pure water: 0을 solubility in 0.0030 M NaOH solution: Data BaSO4 caco CaF2 Co(OH)2 CuBr Cuco; Fe(OH)2 PbCO3 PbCro4 PbF2 Mg(OH)2 NI(OH)2 AgBros Ag2003 1.08x10-10 3.36X10-9 3.45x10-11 5.92 x 10-15 6.27X10-9 1.4x10-10 4.87x10-17 7.40X10-14 2.8x10-13 3.3x10-8 5.61x10-12 5.48x 10-16 5.38x10-5 8.46x10-12...
he solubility product (Ksp) of PbBr2 is 8.9 X 10. Please calculate the molar solubility in: A) Pure water B) 0.20 M Pb(NOs)2 Pb Brs) Pbap +2 Br 8.9- M0T 2 LOZJLES . 45 25 O.Zts Zs 4.45./05 4 4s 0.2x0.2+s 13:105- J S0-60334 9. The solubility of an ionic compound MX (molar mass = 346 g/mol) is 4.63 X 103 g/L. What is the Ksp for this compound? HoW