Homework Answers
Solution :-
given data :
From given histogram, we can construct the table as below.
| Class | Frequency |
| 63 - 66 | 1 |
| 66 - 69 | 9 |
| 69 - 72 | 10 |
| 72 - 75 | 8 |
| 75 - 78 | 16 |
| 78 - 81 | 13 |
| 81 - 84 | 17 |
| 84 - 87 | 9 |
| 87 - 90 | 12 |
| 90 - 93 | 3 |
| 93 - 96 | 2 |
| Total | 100 |
Part 3 :-
Now consider, the number of students more than 84 inches tall, i.e
Number of students more than 84 inches tall = 9 + 12 + 3 + 2
= 26
Now consider , The Percentage of students more than 84 inches tall , i.e,
The Percentage of students more than 84 inches tall = 26/100
= 26%
The Percentage of students more than 84 inches tall = 26 %
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little lose on step #3
1. The following data set represents the amount spent (in dollars) by 45 shoppers at a supermarket. Construct a frequency distribution for the variable, and also report the relative frequencies for each class in your frequency distribution. NOTE: the data is in dollars and cents; you can not change that data! 1081, 1269, 1378, 15.23, 15.62. 17.00, 17.39. 18.36. 1843. 1927, 19.50.1954. 20.16, 20.59, 22.22, 23.04, 2447. 24.58, 25.13, 26.24.26.26, 27.65, 28.06, 28.08, 28.38, 32.03,...
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For questions 1 to 5: A group of 60 university students wrote a test and obtained the following marks (percentages). 5364 72927364 33 7561 84 | 65 58 76 536374 56 71 58 81 75 69 77 65 78 58 41 37 61 79 4074 | 31 | 39 68 75 | 67 89 59 57 | 39 | 71 | 38 | 66 | 69 81 5340 67 62 60 35 37 75 49 36 58 62 46 These...
ath 131-Statistics Spring 2019 Linked Marjana Aktar & I 1/20/19 5 1 Frequency Distributions for Organizing and Summarizing Data 2.1.15 represents the daily raintall (in inches) for one 0230 0445 The data Construct a frequency distribution beginning with a lower class limit 0 31 of 0.00 and use a class width of 0 20. Does the frequency distribution appear to be roughly a normall distribution 1 27 0.16 15 0 140 0.160550 o 01 002 024 0 14 Daily Rainta...
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