Question

draw your cyclic model by adding the OH groups and H atoms to figure below.

le the drawing a Unded black atom white atoms. Cl, use green For Br, use pe For all Lone chiral Cater b. Convert the open form of ribose into a eyelie form. Here's how: 1. Pull apart one of the Co bonds from the Catom, leaving the other end of the bond attached to the O atom. . Connect the free bond from the O atom at C#4 to C#. This creates a 5-membered ring. 2. Pull the H atom from the O 3 atom attached to C#4. Place this H atom on the free bond of the atom at C#1 (this is the bond that you disconnected from the Cof the C-0.) H-O LAH -OH H2oH на он н -он CH OH H- OH H2-OH H-90- н- он не он н он H-40 CHOH SHOH c. Draw your eyelic model by adding the OH groups and H atoms to the figure below. Make certain that your model is oriented with the O at the back and the HOCHy on the top. There are two correct answers for the orientation of the OH group at C#1, depending on which C-O bond you pulled apart in step #1 directly above. HOCH Why is there no OH group on C#4 of the cyclic sugar?

Answer 1

group on the right of Fischer projection is directed down in Haworth projection whereas group on the left is directed up.

доире и on on

There is on OH on C4 as this OH intially present undergoes cyclization with carbonyl carbon and forms the ring.