Question

i was given this asnwer but i still don't understand how ghe numbers below the second row were found. im looking to inderstand peak number, ppm, integration and proton number

No Service 8:06 PM Answer 1 of 1 Done Elemental enalysis C H 51.7/12 6.89/1 4141/16 259 4.31 6.89 166 2661 0 166 583 C-O, overtone Formula of unknowncompound is CHyO CH, stretching alkane Double bond equivalent C-1-H/2 5-1-8/2 2 Means compound has either two double bonds two rings or one double bond and one ring CO, stretching ketone CH, bending alkane Based on the given deto the structure of unknownis Two peoks in aliphatic reasen represent only twe different types of H in unknown compound. aceouyl acet

Answer 1

The Elemental Analysis is given C-519% H- 689% remaining is arygen that 100 - (51+1+689) = 41.41 In the determination of molecular formula filom Elemental Analysis ist we have to divide the & by its atomic mass. Then we have to didvide all the values with least value of the three to get emprical by molecular tuemula as show n C Ho CH o to 51.7 689 41.41 = = 4.30 689, 2.59 . 48 12 [ 16 = = 4:30, 689, 2.59, 4.80 689 2169 - 259 259 259 However. These values are not inligens so 166, 2:66, I wehe I we have to conveet them integers values by multidying with a common number here it is 6. 1.66X6, 266x6, 1X66 = 29.96 H 15:96 06 - So Go HGO It is emperical formula CHIGO morcarlou colight a emporical formula is = 232, however molestar Ton peak is at 116.1.50 molecular formula is Cg HgOg since the catio of masses are li2. so molecular formula = C5H8O3 Degree of cusatuation - C-(W)+ - 5- +1=2 so the compound has two double bonds. on rings IR Specteum * Small Peak at b 3450 um belongs to c-o stretching ovetone * peak at 2450 cm belongs to alkane C-H steetching * Peak at 17200m belongs to { stretching of esteet * Peaks at 1440cmt and 1380 cm belongs to cH bending & Peak at 12.50 an' belongs to costretching of estr, so the compound is an aliphatic esta.

and It dogsuot red to crygen HOMR specteum * Singlet at chemical shift 8 4.30pm with integrations belongs to CHy group attached to cuygen and have any peotons on neighbour cobon. & singlet at S 2:0 ppm with integration of 4:53. Generally integration we have to does not match exact pestons, we have to consider based on moleculae fermula. So tubo Cho Groups at same chemically equivalent. does not contain neighbour carbon atom' pestons due to singlet, based upon the data the structure of the compound is .... IHNMR values CH3&O-CH₂_&_CH3 CH₂ Coreta B_CH3 (20,3) (4:33) (20,3).