To find out the percent yield, first we will calculate the number of moles used in the reaction to determine limiting reagent in the reaction.
Number of moles of 1-indanone = 0.20/132.16 = 0.0015 moles
Number of moles of 3,4-dimethoxy benzaldehyde = 0.25/166.17 = 0.0015
Both the reactant are in 1:1 ratio and we can take any of the molecule for the calculation of percent yield (the limiting reactant should be taken for percent yield calculation)
Therefore, 166.17 gm of 3,4-dimethoxy benzaldehyde gives 280.3 gm of product
Then, 0.25 gm of 3,4-dimethoxy benzaldehyde will give x gm of product
Amount of product expected (theoretical yield) = (0.25*280.3)/166.17 = 0.42 gm
Amount of product obtained in the reaction = 0.171 gm
Percent yield of reaction = (0.171/0.42)*100 = 40.71%
the top half of the image depicts the synthesis of 2-[(3,4-dimethoxyphenyl)methylene]-2,3-dihydro-1H-inden-1-one from 1-indanone and 3,4-dimethoxybenzaldehyde. The...
Provide a stepwise mechanism for the formation of 2-[(3,4-dimethoxyphenyl)methylene]-2,3-dihydro-1H-inden-1-one from 3,4-dimethoxybenzaldehyde and 1-indanone. Please show all steps! This is a crossed aldol condensation. Thanks! Crossed aldol condensation of 3,4-dimethoxybenzaldehyde and l-indanone CHO CH,0 NaOH spolu co m ments CH,O CH,09 enolate formation OH -H,0 T dehydration CHO OH O CH,0 CHOA carbonyl addition CH,0 initial aldol product