Question

If a 17.5 mL sample of 1.2 M solution of each of the following acids is reacted with 0.85 M NaOH, how many milliliters of the NaOH are required for the titration? What is the total volume (in mL) of solution at the equivalence point? (a) 17.5 mL of HF titrated with 0.85 M NaOH volume of NaOH mL total volume mL (b) 17.5 mL of H2SO4 titrated with 0.85 M NaOH volume of NaOH mL total volume mL c) 17.5 mL of HI titrated with 0.85 M NaOH volume of NaOH ml total volume mL

Answer 1

Write the reaction between HF and NaOH as follows HF + NaOH — NaF+H,O molarity of HF, M, = 1.2M volume of HF, V1 = 17.5 mL molarity of NaOH, M, = 0.85 M Volume of NaOH, V, = ? At equivalence point, MV = M V Substitute the corresponding values in the above relation - 1.2 Mx17.5 mL 0.85M V = 24.7 ml Calculate the total volume as follows: total volume = volume of HF + volume of NaOH = + = 17.5 mL +24.7 mL = 42.2 mL Therefore, the volume of NaOH is (24.7mL and total volume is 42.2 mL) - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - (6) Write the reaction between H SO, and NaOH as follows: H2SO4 + 2NaOH →→ Na2SO4 +2H,0 molarity of H2SO4, M1 = 1.2M volume of H2SO4,71 = 17.5 mL molarity of NaOH, M, = 0.85 M Volume of NaOH, V = ? At equivalence point, MV = Megles Substitute the corresponding values in the above relation y_2MV 2x1.2 Mx17.5 mL 0.85M V = 49.4 mL Calculate the total volume as follows: total volume = volume of H,SO, + volume of NaOH = V1 +1 = 17.5 mL +49.4 mL = 66.9 mL Therefore, the volume of NaOH is 49.4 mL and total volume is 66.9 mL)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Write the reaction between HI and NaOH as follows: HI + NaOH —— NaI+H, O molarity of HI, M= 1.2 M volume of HI, V = 17.5 mL molarity of NaOH, M, = 0.85 M Volume of NaOH, V = ? At equivalence point, MV = MV Substitute the corresponding values in the above relation V2 = Mh - 1.2 Mx17.5 mL 0.85M V = 24.7 ml Calculate the total volume as follows: total volume = volume of H,SO. + volume of NaOH = V1 + V2 = 17.5 mL +24.7 mL = 42.2mL Therefore, the volume of NaOH is 24.7mL and total volume is 42.2 mL)