Please help!
I must have used every equation a hundred different ways, and I
still cant get the answer to #4!
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Please help!
I must have used every equation a hundred different ways, and I
still cant...
Could I get help with these problems please. For the first problem are we using two...
Could I get help with these problems please. For the first
problem are we using two different equations. Are we using a
horizontal and vertical equation. V(t)=axt+vox. I am confused
here
Suppose a baseball player throws a ball. When she releases the ball, her hand is 1 meter above the ground, and the ball leaves her hand at 18 m/s in a direction that makes a 32° angle with the horizontal. (a) What is the maximum height above the ground...
I need the answers with steps please! 10. A boy throws a ball with an initial...
I need the answers with steps please!
10. A boy throws a ball with an initial velocity of 25 m/s at an angle of 30° above the horizontal. If air resistance is negligible, how high above the projection point is the ball after 2.0s? How long is it in the air, and how far does it go before hitting the ground? 11. A projectile leaves the ground at 150 m/s and reaches a maximum height of 0.57 km. If there...
Could I get help with these problems please. For the first
problem are we using two different equations. Are we using a
horizontal and vertical equation. V(t)=axt+vox. I am confused
here
Suppose a baseball player throws a ball. When she releases the ball, her hand is 1 meter above the ground, and the ball leaves her hand at 18 m/s in a direction that makes a 32° angle with the horizontal. (a) What is the maximum height above the ground...
I need the answers with steps please!
10. A boy throws a ball with an initial velocity of 25 m/s at an angle of 30° above the horizontal. If air resistance is negligible, how high above the projection point is the ball after 2.0s? How long is it in the air, and how far does it go before hitting the ground? 11. A projectile leaves the ground at 150 m/s and reaches a maximum height of 0.57 km. If there...
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