Question

Assignment Score: 233/2000 Resources Hint Check Answer < Question 13 of 20 > When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO,(s) + 2 HCl(aq) CaCl (aq) + H2O(l) + CO2(g) How many grams of calcium chloride will be produced when 31.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid? mass of CaCl, Which reactant is in excess? Caco, OHCI How many grams of the excess reactant will remain after the reaction is complete? mass of excess reactant:

Answer 1

no of moles of CaCO3   = W/G.M.Wt

                                       = 31/100 = 0.31moles

no of moles of HCl = W/G.M.Wt

                                = 14/36.5   = 0.384 moles

     CaCO3(s) + 2HCl(aq)-------------->CaCl2(aq) + CO2(g) + H2O(l)

1 mole of CaCO3 react with 2 moles of HCl

0.31 moles of CaCO3 react with = 2*0.31/1   = 0.62 moles of HCl is required

HCl is limiting reactant

2 moles of HCl react with excess of CaCO3 to gives 1 mole of CaCl2

0.384moles of HCl react with excess of CaCO3 to gives = 1*0.384/2    = 0.192 moles of CaCl2

mass of CaCl2 = no of moles * gram molar mass

                         = 0.192*111   = 21.3g of CaCl2

2 mole of HCl react with 1 mole of CaCO3

0.384 moles of HCl react with = 1*0.384/2   = 0.192 moles of CaCO3 is required

The no of moles of excess reactant left after complete the reaction = 0.31-0.192   = 0.118moles

The amount of excess reactant left after complete the reaction = no of moles * gram molar mass

                                                                                                   = 0.118*100   =11.8g of CaCO3