Question

please help!

Please show all your calculations for the following problems: Problem 1: Standardization ofa NaOH Solution with Potassium Hydrogen Phthalate (KHP) Please process with the calculations based on the data collected during an experiment done by a student Trial 3 Trial 2 Trial 1 0.42 0.42 0.42 Mass of KHP (g) Initial buret reading (mL) Final buret reading (mL) Volume of NaOH used (mL) 50 50 50 39.1 39.8 39.5 10.9 0-311L 10.5 0.315 L 0.2 O-398 L Volume of NaOH used (L) Moles of KHP Moles of NaOH Molarity of NaOH Average Molarity of NaOH Accepted Molarity of NaOH Percent Error ( % Error ) Percent Standard Deviation ( % 0.2 SD)

Answer 1

The volume of NaOH in liters is:

Trial 1: 0.0105 L

Trial 2: 0.0102 L

Trial 3: 0.0109 L

KHP moles are calculated:

n KHP = g / MM = 0.42 / 204.22 = 0.002 mol

The moles of NaOH are equal to the moles of KHP. 0.002 mol.

The concentration of NaOH is calculated:

[NaOH] = n / V = ​​0.002 / 0.0105 = 0.19 M

Trial 2: 0.20 M

Trial 3: 0.18 M

Average = 0.19 M

The error percentage is calculated:

% error = (0.2 - 0.19) * 100 / 0.2 = 5%

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