Question

Yaestrompoines Calculate the pressure of the gas mixture and the partial pressure of A gas mixture contains 0.600 mol of N,0.300 mol of H2, and 0.250 mol of CH each constituent gas if the mixture is in a 11.0 Lvessel at 27.00°C 1st attempt See Hint See Periodic Table (1 point) Part 1 total pressure in the vessel atm Part 2 (1point) pressure of H atm Part 3 (1 point) pressure of N atm Part 4 (1 point) See Hint pressure of CH 20 OF 25 QUESTIONS COMPLETED <21/2s SUBMIT ANSWER os e

Answer 1

1)

Given:

V = 11.0 L

n = 0.600 + 0.300 + 0.250 = 1.150 mol

T = 27.00 oC

= (27.00+273.15) K

= 300.15 K

  

use:

P * V = n*R*T

P * 11 L = 1.15 mol* 0.08206 atm.L/mol.K * 300.15 K

P = 2.575 atm

Answer: 2.57 atm

2)

Given:

V = 11.0 L

n = 0.300 mol

T = 300.15 K

use:

P * V = n*R*T

P * 11 L = 0.3 mol* 0.08206 atm.L/mol.K * 300.15 K

P = 0.6717 atm

Answer: 0.672 atm

3)

Given:

V = 11.0 L

n = 0.600 mol

T = 300.15 K

use:

P * V = n*R*T

P * 11 L = 0.6 mol* 0.08206 atm.L/mol.K * 300.15 K

P = 1.3435 atm

Answer: 1.34 atm

4)

Given:

V = 11.0 L

n = 0.250 mol

T = 300.15 K

use:

P * V = n*R*T

P * 11 L = 0.25 mol* 0.08206 atm.L/mol.K * 300.15 K

P = 0.5598 atm

Answer: 0.560 atm