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Part C l ReviewI Constants Periodic Table Calculate the partial pressure of Ar in the mixture. A mixture containing 0.767 mol
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Answer #1

T = 25°C = 25+273.15 K = 298.15 K

R = 0.082 Latm/mol.K

Total pressure, P = [n(Ar) + n(He) + n(Ne)]RT/V

P = (0.118+0.300+0.767)×0.082×298.15/10 atm

= 2.9 atm

Pressure of Ar = XP

Mole fraction of Ar, X = 0.118/(0.118+0.300+0.767)

= 0.118/1.185 = 0.0996

Pressure of Ar = 0.996×2.9 atm = 0.29 atm

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