A mixture containing 0.769 mol He(g), 0.321 mol Ne(g), and 0.114 mol Ar(g) is confined in...

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A mixture containing 0.769 mol He(g), 0.321 mol Ne(g), and 0.114 mol Ar(g) is confined in...

A mixture containing 0.769 mol He(g), 0.321 mol Ne(g), and 0.114 mol Ar(g) is confined in a 10.00-L vessel at 25 ∘C.

A. Calculate the partial pressure of He in the mixture.

B. Calculate the partial pressure of Ne in the mixture.

C. Calculate the partial pressure of Ar in the mixture.

D. Calculate the total pressure of the mixture.

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Answer 1

Answer #1

Total mole of gas = Mole (helt mole (Ne) & Mole (Ar) s 1. 204 molese divide with smallest moll number = 0.769 To find mole fr P = (1.204) (0.082) ( 298) 12.94 atm total = 0.638 x 2.94 = 1.87 atm. A. Partial Pressure he => 0.782 atm 0.266 x 2.94 Ne= B.

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Answer 2

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