Question

When the following half reaction is balanced under basic conditions, what are the coefficients of the species shown? B+ OH — H2B03 + H20 In the above half reaction, the oxidation state of boron changes from to - .

Answer 1

108 Answer: - 17 In the given question we have to balanced the chemical reaction and simultaneously have to write the coefficients of the individual species. D o + []04 - H28030 + H20 do we can balance this reaction as a 18 + 4 040-71 H2 BOS + 1 H20 othes coefficients of B = 1 -->) - of OHO = 4 _) — of HBO = I . -)) - of M20 : 1. Now next is we have to find out the change in oxidation atate of boron. .. 18 + 4000 H2 Bogo + 1H2O initially B chave zero oxidation actate. After reaction boron have a oxidation state. - 2x + 4x + 3x C-2 ) = -1 x = -4+4 | 1 = 3 Scanned with CamScanner

80 Expt. No. Experiment: Date : Date : from lie. oxidation state of boron il changes 2x In the aimilar way we will solve this question Пcio + C) H, o –Oce + Доне The reaction is belanced as w 1 clogo + 8 H20 1 ciotoon ie.coefficient of gloge = 1 - )) - H20 = 3 - c = 1 - >) - OHO = 6 Next is we have to find change in oxidation - State of chlorine (cl).. Initially it is present as cing lie. xx1 + 3% (-2) =-|| x = -1 + 6 = +5 . And final oxidation state is crie. -1. Hence oxidation state of chlorine is cheenges from ts to - 2 Thank you cs Scanned with CamScanner